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				中级会员33004732 5143.8 元2014-08-22 | 
				
					
					
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					  发表于 2015-11-09 16:54
					
				
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						  输入以下代码: 2 字节(高位优先) 复制代码alloc(TypeName,256)
alloc(ByteSize,4)
alloc(ConvertRoutine,1024)
alloc(ConvertBackRoutine,1024)
TypeName:
db '2 Byte Big Endian',0   //CE不支持中文m
ByteSize:
dd 2
//The convert routine should hold a routine that converts the data to an integer (in eax)
//function declared as: stdcall int ConvertRoutine(unsigned char *input);
//Note: Keep in mind that this routine can be called by multiple threads at the same time.
ConvertRoutine:
//jmp dllname.functionname
[64-bit]
//or manual:
//parameters: (64-bit)
//rcx=address of input
xor eax,eax
mov ax,[rcx] //eax now contains the bytes 'input' pointed to
xchg ah,al //convert to big endian
ret
[/64-bit]
[32-bit]
//jmp dllname.functionname
//or manual:
//parameters: (32-bit)
push ebp
mov ebp,esp
//[ebp+8]=input
//example:
mov eax,[ebp+8] //place the address that contains the bytes into eax
mov ax,[eax] //place the bytes into eax so it's handled as a normal 4 byte value
and eax,ffff //cleanup
xchg ah,al //convert to big endian
pop ebp
ret 4
[/32-bit]
//The convert back routine should hold a routine that converts the given integer back to a row of bytes (e.g when the user wats to write a new value)
//function declared as: stdcall void ConvertBackRoutine(int i, unsigned char *output);
ConvertBackRoutine:
//jmp dllname.functionname
//or manual:
[64-bit]
//parameters: (64-bit)
//ecx=input
//rdx=address of output
//example:
xchg ch,cl //convert the little endian input into a big endian input
mov [rdx],cx //place the integer the 4 bytes pointed to by rdx
ret
[/64-bit]
[32-bit]
//parameters: (32-bit)
push ebp
mov ebp,esp
//[ebp+8]=input
//[ebp+c]=address of output
//example:
push eax
push ebx
mov eax,[ebp+8] //load the value into eax
mov ebx,[ebp+c] //load the address into ebx
//convert the value to big endian
xchg ah,al
mov [ebx],ax //write the value into the address
pop ebx
pop eax
pop ebp
ret 8
[/32-bit] 
4 字节(高位优先) 复制代码alloc(TypeName,256)
alloc(ByteSize,4)
alloc(ConvertRoutine,1024)
alloc(ConvertBackRoutine,1024)
TypeName:
db '4 Byte Big Endian',0 //db '4 字节 (高位优先)',0
ByteSize:
dd 4
//The convert routine should hold a routine that converts the data to an integer (in eax)
//function declared as: stdcall int ConvertRoutine(unsigned char *input);
//Note: Keep in mind that this routine can be called by multiple threads at the same time.
ConvertRoutine:
//jmp dllname.functionname
[64-bit]
//or manual:
//parameters: (64-bit)
//rcx=address of input
xor eax,eax
mov eax,[rcx] //eax now contains the bytes 'input' pointed to
bswap eax //convert to big endian
ret
[/64-bit]
[32-bit]
//jmp dllname.functionname
//or manual:
//parameters: (32-bit)
push ebp
mov ebp,esp
//[ebp+8]=input
//example:
mov eax,[ebp+8] //place the address that contains the bytes into eax
mov eax,[eax] //place the bytes into eax so it's handled as a normal 4 byte value
bswap eax
pop ebp
ret 4
[/32-bit]
//The convert back routine should hold a routine that converts the given integer back to a row of bytes (e.g when the user wats to write a new value)
//function declared as: stdcall void ConvertBackRoutine(int i, unsigned char *output);
ConvertBackRoutine:
//jmp dllname.functionname
//or manual:
[64-bit]
//parameters: (64-bit)
//ecx=input
//rdx=address of output
//example:
bswap ecx //convert the little endian input into a big endian input
mov [rdx],ecx //place the integer the 4 bytes pointed to by rdx
ret
[/64-bit]
[32-bit]
//parameters: (32-bit)
push ebp
mov ebp,esp
//[ebp+8]=input
//[ebp+c]=address of output
//example:
push eax
push ebx
mov eax,[ebp+8] //load the value into eax
mov ebx,[ebp+c] //load the address into ebx
//convert the value to big endian
bswap eax
mov [ebx],eax //write the value into the address
pop ebx
pop eax
pop ebp
ret 8
[/32-bit] 
最终效果图:    |